Program: C program to add two numbers
#include<stdio.h> int main() { int num1, num2, sum; printf("\nEnter two numbers: "); scanf("%d %d", &num1, &num2); sum = num1 + num2; printf("Sum: %d", sum); return(0); }
Output
Enter two numbers: 4 5
Sum: 9
Program: addition of two numbers in c
#include <stdio.h> int main() { int number1, number2, add; printf("Enter two integer numbers: "); scanf("%d %d", &number1, &number2); // calculating sum add = number1 + number2; printf("%d + %d = %d", number1, number2, add); return 0; }
Output
Enter two integer numbers: 10 10
10 + 10 = 20
In this example, the user is asked to enter two integer numbers and then the program displays the sum of these two numbers.
#include <stdio.h> int main() { int number1, number2, sum; printf("Enter the first number: "); scanf("%d", &number1); printf("Enter the second number: "); scanf("%d", &number2); sum = number1 + number2; printf("Sum of the two numbers are: %d", sum); return 0; }
Output
Enter the first number: 10
Enter the second number: 10
Sum of the two numbers are: 20
C program to find the sum of two numbers using a user-defined function. The function adds two numbers and returns the result of the addition.
#include <stdio.h> int sum2number(int num1, int num2){ return num1+num2; } int main() { int number1, number2, sum; printf("Enter the first number: "); scanf("%d", &number1); printf("Enter the second number: "); scanf("%d", &number2); //Calling the function sum = sum2number(number1, number2); printf("The Sum of the entered numbers are: %d", sum); return 0; } Output
Enter the first number: 10
Enter the second number: 10
The Sum of the entered numbers are: 20
You can also use the bitwise operator to find the sum of two numbers.
int sum(int num1, int num2) { while (num2 != 0) { int carry = num1 & num2; num1 = num1 ^ num2; num2 = carry << 1; } return a; }0 0
In this example, I will show you how we can add two numbers without using the + operator.
#include<stdio.h> int main() { int a,b; a=10; b=20; int sum; sum=a-(-b); printf ("Sum of two numbers are %d",sum); return 0; }0 0
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